Maths Functions, Limits, Continuity and Differentiability JEE (Advamced) / IIT - JEE Problems ( Previous Year ) Single Correct MCQ
Published on: August 14, 2026

Let f : → R and g : → R be functions defined by f(x) = [x 2 – 3] and

g(x) = |x| f(x) + |4x – 7| f(x), where [y] denotes the greatest integer less than or equal to y for y ∈ R. Then

A
f is discontinuous exactly at three points in
B
f is discontinuous exactly at four point in
C
g is NOT differentiable exactly at four points in
D
g is NOT differentiable exactly at five points in .

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
A

(b,c)

Sol. f(x) = [x 2 – 3] = [x 2 ] – 3 =

g(x) = |x| f(x) + |4x–7| f(x)

= (|x| + |4x – 7|) [x 2 – 3] =

=

Now graph of given function is

f(x) g(x)

Clearly F is not discontinuous at exactly 4 point in [–1/2, 2] and g is not differentiable at 4 points in (–1/2, 2) Hence Ans. is BC

──────────────────────────────────────────────────────────────────────────────────────────

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.